Calculating the pH of Gastric Juice from a Frog

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Discussion Overview

The discussion revolves around calculating the pH of gastric juice from a frog that died due to acid ingestion. Participants explore the necessary steps and methods for determining the pH based on the volume of gastric juice and the amount of NaOH required for neutralization. The scope includes mathematical reasoning and conceptual clarification related to acid-base chemistry.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • One participant expresses confusion about how to approach the problem of calculating pH from the given data.
  • Another participant suggests finding the pH of the NaOH solution first and inquires about the methods attempted by the original poster.
  • A participant calculates the pH of the NaOH solution and presents their reasoning, but it is unclear how this relates to the gastric juice pH calculation.
  • One participant advises against needing to calculate pOH and suggests using stoichiometry to find the concentration of HCl in the gastric juice for pH calculation.
  • Another participant proposes using the equation M1V1=M2V2 to find the concentration of HCl, followed by using the concentration to calculate pH.
  • There is a mention of the composition of gastric juice, primarily consisting of HCl, which may aid in understanding the problem.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method for calculating the pH of the gastric juice, with multiple approaches and levels of understanding presented. Some participants express uncertainty about the steps involved.

Contextual Notes

There are unresolved aspects regarding the application of stoichiometry and the specific calculations needed to determine the concentration of HCl from the neutralization reaction.

jena
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Hi,

My Question:

Upon evisceration, it was discovered that the frog had died due to acid ingestion. 10mL of gastric juice was found in its stomach required 7.2mL of 0.1 M NaOh for neutralization. Calculate the pH of its gastric juice.

I'm confused, how would I approach this problem.

Thank You:smile:
 
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jena said:
Hi,

My Question:

Upon evisceration, it was discovered that the frog had died due to acid ingestion. 10mL of gastric juice was found in its stomach required 7.2mL of 0.1 M NaOh for neutralization. Calculate the pH of its gastric juice.

I'm confused, how would I approach this problem.

Thank You:smile:
Well first you might want to find the pH of the NaOH solution. Also, what have you tried?

Alex
 
So it would be like this

poH=log[H]
poh=-log[0.1]
poH=1

and

ph+poH=14
ph+1=14
ph=13

Is this correct:confused:

thank you
 
jena said:
So it would be like this

poH=log[H]
poh=-log[0.1]
poH=1

and

ph+poH=14
ph+1=14
ph=13

Is this correct:confused:

thank you
That looks good for the pH of the NaOH solution. Now, you want to find the pH of the gastric acid. Do you know how to do so from here?

Alex
 
No:cry: , I still don't know what to do. Also what do I do with the mL's

Thank You:smile:
 
No need for pOH.

Calculate from simple stoichiometry amount of HCl in the gastric juice, then its concentration - once you know concentration of HCl pH calculation should be a breeze.
 
Sorry to reply so late, so I would first find the concentration like so,

M1V1=M2V2

and then use the concentration to find the pH of the acid using this equation

ph=-log(H+)

Is that the correct method?

Thank You
 
Show what you did as your answer about using M1V1=M2V2 is ambiguous.
 
Wouldn't it help if you knew the formula of the gastric juice?
 
  • #10
P-man - gastric juice contains mostly HCl.
 
  • #11
Oh, sorry. I guess that's the stuff in your stomach?
 

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