Did I put this truth table in the k-map correctly?

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Discussion Overview

The discussion revolves around the correctness of a Karnaugh map (K-map) derived from a truth table. Participants are examining the mapping of values and potential errors in the K-map representation, focusing on the application of boolean algebra for simplification and verification.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses uncertainty about their K-map, noting they received different answers upon multiple attempts.
  • Another participant identifies an error in the K-map, specifically mentioning the presence of two c' entries that do not match the original truth table.
  • A participant seeks confirmation on the placement of 1's in the K-map, listing specific binary combinations.
  • Another participant suggests using boolean theorems to simplify the expression and check the K-map, providing a detailed breakdown of the simplification process.
  • There is a claim that the participant made a mistake in the K-map by misrepresenting a term as AB'C' instead of AB'C.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus, as there are conflicting views regarding the correctness of the K-map and the identification of errors. Multiple competing interpretations of the K-map and truth table remain present.

Contextual Notes

Limitations include potential misunderstandings of boolean simplification steps and the accuracy of the K-map entries based on the original truth table. The discussion does not resolve these issues.

mr_coffee
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Hello everyone, I need to you to check if i did this right, i did this k-map 3 different times and everytime i do it, i get a different answer. okay here is the picture:
http://img212.imageshack.us/img212/109/lastscan3ga.jpg

also here it is at another location:
http://show.imagehosting.us/show/772450/0/nouser_772/T0_-1_772450.jpg
Thanks.
 
Last edited by a moderator:
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no, you have an error. you have two c' entries on thr map but only one in the original truth table.
 
so the 1's should be here:
011
101
111
110
right?>
 
You could simplify using boolean theorems to check your answer.

z= A'BC+AB'C+ABC'+ABC

The last term ABC, has at least two variables common in the other terms.

Z = A'BC+ABC+AB'C+ABC+ABC'+ABC
Z = BC(A'+A) + AC(B'+B) + AB(C'+C)
Z = BC + AC + AB

You have BC + AC' + ABThe mistake that you made in the K-map is that you have AB'C' instead of AB'C.
 
Last edited:

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