Calculating Degree of Polarization at Air-Glass Interface

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Homework Help Overview

The discussion revolves around calculating the degree of polarization of light at an air-glass interface, specifically focusing on transmitted and reflected light at a given angle of incidence. The subject area includes optics and electromagnetic theory, particularly the behavior of light at material boundaries.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive expressions for the degree of polarization for both transmitted and reflected light, while also considering Brewster's angle. Questions are raised about identifying polarized light and calculating intensities for polarized versus unpolarized light.

Discussion Status

Some participants have offered guidance on the nature of the problem, suggesting that the boundary conditions between air and glass need to be considered. There is a mention of using Fresnel relations to determine the relative intensities of reflected and transmitted light for different polarizations. Multiple interpretations of the problem are being explored, particularly regarding the treatment of incident light as a mixture of polarizations.

Contextual Notes

Participants note that the original poster may be working within the framework of a course covering electromagnetic fields and their interactions with materials. There is an implication that prior knowledge of reflection and transmission at planar interfaces is expected.

TimNguyen
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A beam of natural light is incident (from the air) on an air-glass interface at 40 degrees. Take n = 1.5 for the glass.

a)Obtain an expression for the degree of polarization of the transmitted light and compute it numerically.

b)Obtain an expression for the degree of polarization of the reflected light and compute it numerically.

c)Obtain an expression for the degree of polarization of the transmitted light when the angle of incidence is Brewster's angle and evaluate it numerically.

The only formula that I'm given is that the degree of polarization is equal to I(polarized) / [I(polarized) + I(unpolarized)].

How do I know which light is polarized and obtain the intensity for each polarized/unpolarized light?
 
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Could anyone help out?
 
It might help if you mentioned what kind of class you're taking and what sort of other things you've been studying.

I'm going to guess that you're taking a class where you're discussing the electric and magnetic fields associated with light.

The problem amounts to determining the boundary conditions between E&M in air and E&M in glass. The solution is that the tangential E&M fields are continuous and that this is enough to define the changes in angles.

You will have to work it out twice, once with light polarized one way and once with light polarized the other. That is, one way the E field is tangential to the surface, the other way the B field is tangential.

After you get the transmission and reflection coefficients for the two ways light can arrive, you will see that there is a difference in how much they reflect and transmit. That makes the light that is reflected polarized even if the light coming in wasn't. That's what you're calculating.

Good luck, it's a tough assignment.

Carl
 
TimNguyen said:
The only formula that I'm given is that the degree of polarization is equal to I(polarized) / [I(polarized) + I(unpolarized)].

How do I know which light is polarized and obtain the intensity for each polarized/unpolarized light?


You must have had something that's called "reflexion and transmission at planar interfaces", no ?
Look for something called "Fresnel relations" which give you the relative intensities of reflected and transmitted light incident under an angle for the two polarizations (perpendicular and parallel to the reflecting surface).

As CarlB suggests, consider the incident light as a 50-50 mix of both, and then see what fraction survives after reflexion or transmission and how much it deviates from this 50-50 ratio in both cases.

cheers,
Patrick.
 

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