How Do You Calculate Backward Power and Forces in Physics Problems?

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Homework Help Overview

The discussion revolves around calculating backward power and forces in physics problems, specifically in the context of a cyclist accelerating and a person suspended in a helicopter. The original poster presents two scenarios involving force calculations and seeks assistance in understanding the underlying concepts.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to consider friction and air resistance in the cyclist's problem. Questions arise about how to calculate the backward force when the cyclist exerts a forward force of 150N. The original poster also seeks clarification on the forces acting on a person in a helicopter during different phases of motion.

Discussion Status

Some participants have provided insights into the calculations and concepts involved, while others express confusion about the nature of the help being offered. There is an ongoing exploration of how to approach the problems without providing direct solutions.

Contextual Notes

Participants note the importance of understanding net forces and the effects of acceleration and gravity in the given scenarios. There is a mention of the gravitational constant in relation to the second problem, indicating a need for careful consideration of all forces at play.

Izekid
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A competition-cyclist closing the goal. Towards the end-rush she raises her speed from 12m/s to 20m/s on 6.5s. The Cyclist and the cycles masses are together 70kg. Calculate acceleration The acceleration is 1,23 no problem i calculated that but the next question is hard.

The Cyclist pushes forward a power of 150N. How much power is pushing backwards. Which types of powers are there?
How shall i Calculate the power backwards here?

To the second problem...

A person who weights 76,5kg hangs up in a helicopter with a line. Which powers utilizes the person and how big are theses powers.

a) In the beginning when the acceleration is 1,3m/s^2
b)When the speed is constant with 2.0m/s
c)On the top, where the acceleration is -1,3m/s^2

How do i calulate this? My mind stands still... please help me

Thanks
Izekid
 
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F = ma, where F is the net force. Is this enough help?
 
Nope in the cyclist problem you shall calculate with Friciton and Air-resistance.
And the result backwards shall be 64N.


The second problem I resolved by myself :smile: :smile: :smile: :smile: :smile:
Because 76,5 * 9,82 = 751,23 N
and 76,5 * 1,3 = 99,45 N = 850,68N =0,85kN
And so on (I forgot to take the gravitionconstant)

But PLZ help me with the cyclist...
 
As the forces added must result ma:
[tex]F_f + (-F_b) = ma[/tex]
f stands for forward, and b for backward.
 
Päällikkö said:
F = ma, where F is the net force. Is this enough help?
?
Sorry, I just wonder what kind of help is that?
Izekid said:
The Cyclist pushes forward a power of 150N. How much power is pushing backwards. Which types of powers are there?
How shall i Calculate the power backwards here?
I wouldn't use power here... I'd use force instead.
So you know that the cyclist has an acceleration of 1.23 m /s2. You also know his mass (his own mass, and the bicycle mass), so you will be able to calculate the net force acting on him, right?
Fnet = ma = ...
Then you will have Fnet < 150 N, right?
He's pulling himself forward with a force of 150 N, but the net force on him is less than 150 N, so there must be some force that slow him down, ie it acts in the oposite direction. Can you find the magnitude of that force?

For #2, you seem to forget #c :wink:
The net force for c will be:
Fnet = ma = 1.3m.
Remember that he's decelerating, so the net force will point down (since he's moving upwards).
Viet Dao,
 
Last edited:
thx that did it
 
VietDao29 said:
?
Sorry, I just wonder what kind of help is that?
Granted, it wasn't much help. I'd call it more like a reminder. In a problem like this, there isn't mighty lot one can say without solving the problem. I didn't want to give away the answer, as I personally hate being guided too much.
 

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