What is the coefficient of static fraction for the book?

Click For Summary

Homework Help Overview

The discussion revolves around determining the coefficient of static friction for a book resting on a tabletop. The original poster presents a scenario where a 1.8 kg book requires a force of 2.25 N to initiate sliding, prompting questions about the necessary calculations and concepts involved.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between frictional force and normal force, with some questioning the calculations of forces involved. There is a focus on understanding how to derive the coefficient of static friction from the given forces.

Discussion Status

The discussion is active, with participants providing insights into the relationships between forces and questioning the calculations made by others. Some guidance has been offered regarding the use of Newton's laws and the relationship between friction and normal force, but no consensus has been reached on the correct approach to find the coefficient of static friction.

Contextual Notes

Participants are navigating potential misunderstandings regarding the calculation of forces, particularly the normal force and frictional force. There is also a mention of the need to clarify whether the goal is to find the acceleration of the book or the coefficient of static friction.

Raiden9
Messages
10
Reaction score
0
I really don't know where to find the acceleration of the object in this question.

When you push a 1.8 kg book resting on a tabletop, it takes 2.25 N to start the book sliding. Hwat is the coefficient of static fraction?

Any help would be greatly appreciated, I have already done the force diagram and equations, found Fg and Fn, I just don't know how you would find the acceleration of the object.

Thank You!
 
Physics news on Phys.org
[tex]F_\mu = \mu N[/tex]
Fmu being the force caused by friction, mu the coefficient of friction and N the force the surface exerts on the object.

Using Newton's III, in your problem, can you figure out the force exerted on the book by the table?
 
I found out that it was 931N. But then where would I go with that? Because I would need to find the Ff then divide that by 931N.

Thank You!
 
How did you get 931 N? That is a big force for a book with a mass of only 1,8kg:
F = ma <=> a = F/m = 931 N / 1,8 kg = 517 m/s^2.

If by Ff you mean Fmu, the force caused by friction, you already know its maximum magnitude.
 
I was looking at the problem! I am sorry! I got 17.64 for the Force of book (Fn) on the table. Now, would why I take that since if I got that answer I would take Fn=17.64/mass=1.8 equals the acceleration. Wouldn't I need to find the Ff first then take that and divide it by the mass?
 
Hey there!
May I know whether you want to find the acceleration of the book when it begins to slide, or the coefficient of static friction in this question?
 
Raiden9 said:
I got 17.64 for the Force of book (Fn) on the table. Now, would why I take that since if I got that answer I would take Fn=17.64/mass=1.8 equals the acceleration. Wouldn't I need to find the Ff first then take that and divide it by the mass?
Don't think that you need to know the acceleration in order to find the force! For one thing, Newton's 2nd law says that the net force equals ma. In this case, the net force is zero--it just barely begins to slide. So that won't help you.

Note that you are given the friction force. Use the formula that Päällikkö gave for relating the maximum static friction to the normal force.
 

Similar threads

Replies
6
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
7
Views
2K
Replies
61
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K