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Buffon's Needle problem (Geo Prob) |
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| Oct16-05, 05:24 PM | #1 |
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Buffon's Needle problem (Geo Prob)
http://www.mste.uiuc.edu/reese/buffo...html#questions
can someone explain problem "A" for me please. this isn't for school or hw but just something that i dont understand and would like to know where i'm going wrong. how would i go about solving question "A"? thanks |
| Oct16-05, 10:16 PM | #2 |
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There is no question A. Did you mean q.1?
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| Oct16-05, 11:16 PM | #3 |
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| Oct17-05, 09:00 AM | #4 |
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Buffon's Needle problem (Geo Prob)
It seems to me that q.1 is asking you to assume 1,000 needle drops with thetas distributed evenly between 0 and pi.
First, renormalize by multiplying all areas by 2/pi. After renormalization the area of the large rectangle is 1 and the shaded area is 2/pi. Prob{hit} = (2/pi)/1 = 2/pi as before. Now you are to approximate the shaded area by calculating the area for 1,000 little rectangles. The 1st little rectangle has area 0. The 2nd has area = base x height x renormalization = (pi/1000) x sin(pi/1000)/2 x 2/pi = sin(pi/1000)/1000. The 3rd has area = (pi/1000) x sin(2pi/1000)/2 x 2/pi = sin(2pi/1000)/1000. The Nth has area = (pi/1000) x sin((N-1)pi/1000)/2 x 2/pi = sin((N-1)pi/1000)/1000. Sum area = [tex]\right.\sum_{N=1}^{1000}\sin\left(\frac{(N-1)\pi}{1000}\right)\left/1000[/tex] It seems to me like this sum area is the approximate 2/pi that the question is after. (This still doesn't make a whole lot of sense to me because pi is parametric in the formula itself; so one must already assume an exact value for it before one can approximate it.) |
| Apr6-07, 06:56 AM | #5 |
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I am working on a practical application of Buffon's Needle for when the length of the needle is greater than the distance between the lines.
I am looking for an EXCEL model to calculate the probability. Thanking You in Advance. |
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