|Oct20-05, 06:51 PM||#1|
Viscosity & bouyant force
hi all just doing some questions and come along these two which have me stumped. There multiple choice questions but id rather know the working out to them as i have exams in a couple of weeks. thanks.
1. The mass of a hot-air balloon and its fully loaded basket is 500kg excluding the air in the balloon. if we assume the balloon is spherical, what radius must the ballon be for it to float if the density of the hot air inside the balloon is 0.95kg/m^3 and the density of the cold air outside is 1.3kg/m^3.
--- with this question i belive you use the P = Po + pgh but i cannot set it out to find the radiusi have tried to use 4/3 pi R^3 where m = pV.
2. A sphere of mass 1.9g & diameter 8mm made of steel is dropped into a tank of liquid with density = 900kg/m^3 and falls a distance of 30cm in 27 seconds. What is the Viscosity of the oil?
--- i looked through text books but i could only find newtons law for viscosity and i had no idea how to work it out.
and just one quick check i believe this is right.
Newtons law of viscosity says that: - the stress depends on the acceleration( i belive this is it because the equation is stress is the viscosity of the liquid x the change in velocity i believe?)
the other options for the answer were
1. the stress is proportianal to the rate of strain
2. The velocity gradient is linear.
but i see no relation with these other 2 answers.
any help is much appreciated thanks!
|Oct21-05, 11:48 PM||#2|
Pressure inside the hot-air balloon is the same as the
Pressure outside the balloon, at the bottom of the bag.
The cold air is "Buoyant enough" to hold up a Volume of cold air.
The basket mass + hot air mass should be the same amount
as the cold air mass that the same Volume encloses.
the gradient of velocity is linear ...
at the falling ball surface, the oil has same velocity as the ball.
the oil is dragged slightly slower, at a ring slightly larger than ball.
CHANGE in velocity (time-wise) is totally distinct from
Difference in velocity (at different places) .
z-component of v_ball - v_oil is proportional to r-R .
|Oct22-05, 07:44 AM||#3|
This might help on viscosity
In the first part, one is concerned with bouyancy.
As lightgrav indicated, the effective density of the balloon (total mass including hot air, balloon and basket divided by volume of hot air) must be equal to the density of cold air. Or mass mass of balloon and hot air must equal mass of cold air displaced by balloon.
In the second problem, a metal sphere falling through oil is subject to bouyant force and drag (resistant force). The drag is determined by the viscosity of the oil.
One can calculate how fast the steel ball would fall (or accelerate) in air (neglecting air resistance) and compare to how fast it falls in oil.
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