Solving Fourier Series Prob: Need Help With Integral Parts

Click For Summary
SUMMARY

The discussion focuses on solving a Fourier series problem involving integration over specific intervals. The user is integrating from 0 to π and is confused about the integration limits, particularly from 0 to π/2. It is established that |cos(x)| can be simplified to cos(x) from 0 to π/2 and -cos(x) from π/2 to π. The user also discusses modifying the integration limits from -l to l to 0 to l, adjusting the integral multiplier from 1/l to 2/l for accuracy in the context of the fundamental period.

PREREQUISITES
  • Understanding of Fourier series concepts
  • Knowledge of definite integrals and integration techniques
  • Familiarity with trigonometric functions, specifically cosine
  • Basic principles of periodic functions and their properties
NEXT STEPS
  • Study the properties of Fourier series and their applications in signal processing
  • Learn advanced integration techniques, focusing on piecewise functions
  • Explore the implications of changing integration limits in Fourier analysis
  • Investigate the use of symmetry in integrals involving periodic functions
USEFUL FOR

Mathematicians, engineering students, and anyone involved in signal processing or harmonic analysis who seeks to deepen their understanding of Fourier series and integration techniques.

math&science
Messages
24
Reaction score
0
I've got parts of this problem but I'm stuck on some of the integration. See attached. Thanks!
 

Attachments

Physics news on Phys.org
First, since an interval is 0 to [itex]\pi[/itex] what are you integrating over 0 to [itex]\pi/2[/tex]?<br /> <br /> Second, since cos x is positive from 0 to [itex]\pi/2[/itex] and negative from [itex]\pi/2[/itex] to [itex]\pi[/itex], you can replace |cos(x)| with <br /> cos(x) from 0 to [itex]\pi/2[/itex] and with -cos(x) for [itex]\pi/2[/itex] to [itex]\pi[/itex].[/itex]
 
HallsofIvy said:
First, since an interval is 0 to [itex]\pi[/itex] what are you integrating over 0 to [itex]\pi/2[/tex]?<br /> Second, since cos x is positive from 0 to [itex]\pi/2[/itex] and negative from [itex]\pi/2[/itex] to [itex]\pi[/itex], you can replace |cos(x)| with <br /> cos(x) from 0 to [itex]\pi/2[/itex] and with -cos(x) for [itex]\pi/2[/itex] to [itex]\pi[/itex].[/itex]
[itex] <br /> I changed the interval I was integrating over b/c that's part of the equation. You can't integrate from -l to l so you change it to 0 to l where l is half of the fundamental period and instead of multiplying the integral by 1/l, I changed it to 2/l. Is it easier to just integrate from -l to l?[/itex]
 
Last edited:

Similar threads

Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
2K
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K