| Thread Closed |
Motorcycle Wheel of Death |
Share Thread | Thread Tools |
| Oct24-05, 07:45 AM | #1 |
|
|
Motorcycle Wheel of Death
Some pointers would be greatly appreciated please.
A motorcycle is slowing down, but maintaining its height on a 'wall of death' (a vertical cylinder where the motorcycle 'drives' around the inner circumference as a stunt). A spectator takes timings in milliseconds as the motorcycle passes a set point. Armed with only these timings, the wall dimensions and the time at which the motorcycle dropped, how might I determine the actual speed at which the motorcycle finally falls off the wall, and the position around the wall relative to the timing point (or total distance covered since any one of the timings) when this happens. I'm not sure that the basic equations of constant acceleration will work out here as I assume friction will be a factor which decreases as the cycle speed decreases. It's been 20 years since I sat in a maths / physics lesson and any help would make me look like the intelligent father I often pretend to be! Thanks to all. |
| Oct24-05, 11:54 AM | #2 |
|
Mentor
Blog Entries: 1
|
Apply Newton's 2nd law to both the vertical and horizontal directions. In the horizontal direction, the acceleration is given by the usual centripetal acceleration formula. In the vertical direction, there is equilibrium. |
| Oct25-05, 04:10 PM | #3 |
|
|
1.) Gravity (but I don't know the mass of the motorcycle) 2.) The centripetal force from the wall acting towards the centre (again, I don't know the mass) - a portion of which (but I'm not sure what portion) is counteracting gravity and keeping the height constant. 3.) Friction of the tyres against the wall, the wheels bearings and the motion through air. I was kind of hoping that it would be possible to calculate the overall friction coefficient from the timings I would have (as these are at a set distance which is the circumference of the wall, which I also have), and this would allow me to extrapolate the deceleration. As I know the time that the cycle falls I would then be able to work out the speed, and with some other magic formula, which I also don't posses, work out the area under the 'velocity - time' line and calculate distance travelled. Sorry that I've not yet seen the light, but any chance of another pointer or two. Thanks again. |
| Oct25-05, 07:07 PM | #4 |
|
Mentor
Blog Entries: 1
|
Motorcycle Wheel of Death(1) Gravity (equals mg), acting down.As long as the motorcyle is not slipping down the wall, then we know that vertical forces must be in equilibrium. Thus: f = mg. We also know that the normal force must produce the centripetal acceleration. Thus: [itex]N = m v^2/r[/itex]. If the speed is too low, the normal force will not be able to provide enough friction to support the weight of the motorcycle. I hope this helps a bit. I'm not exactly sure what problem you are solving, and what data you have. Is the motorcyle speed decreasing at a constant rate? If you know the speed at which it begins to slip, then you can use that to find the coefficient of friction. |
| Thread Closed |
| Thread Tools | |
Similar Threads for: Motorcycle Wheel of Death
|
||||
| Thread | Forum | Replies | ||
| Near Death Studies - Consciousness After Death | General Discussion | 87 | ||
| What motorcycle to buy? | General Discussion | 62 | ||
| Motorcycle carrier | Mechanical Engineering | 0 | ||
| thermodynamics motorcycle | Introductory Physics Homework | 8 | ||
| My death or death as a real earth non-being. | General Discussion | 0 | ||