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Antiderivatives

 
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Oct30-05, 11:49 AM   #1
 

Antiderivatives


I am taking an Architectural Geometry class, and have only had Precal. We just started antiderivatives (I understand regular derivatives), and had a question:

I have to find the antiderivative of

(-5/12 x^4) + (10/3 x^3) - (103/12 x^2) + (23/3 x)

I think I use the power rule for antiderivates...so far i have the first function to be

(-5/12 x^5)/(5)

is that right? if so, does it simplify to -.083x^5? This is where i get confused. Later on I will need to plug in a variable for x. I just wanted to make sure that I am doing this right so far. Thank you.
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Oct30-05, 12:36 PM   #2
 
yes that is right but if you simpifly it it is just -x^5/12
Oct30-05, 01:06 PM   #3
 
Ok, thanks for the reply. If that's the case, does that make the rest of the equation:

(-x^5) / 12 + (5x^4)/6 - [(103x^3)/12) / 3] + [(23x^2)/3) /2 ]

Thanks again.
Oct30-05, 01:19 PM   #4
 

Antiderivatives


Yes, but you can simplify. I'll take one of your terms.

What's [tex]\frac{103}{12}*\frac{x^3}{3}[/tex]?
Oct30-05, 04:12 PM   #5
 
it would be 103x^3 / 36 . Or do you want it simplified more?
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