Force vs Time Graph: Impulse of a Soccer Ball Kick

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Homework Help Overview

The discussion revolves around calculating the impulse imparted on a soccer ball during a kick, using a force vs time graph. The problem involves concepts from dynamics and impulse-momentum theory.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to integrate the force over time to find impulse but express uncertainty about the integration process without a clear equation. Questions arise about how to interpret the graph and the challenges posed by poor labeling. Some suggest estimating the area under the curve graphically, while others propose modeling the curve as quadratic.

Discussion Status

The discussion is ongoing, with participants exploring different methods of integration and questioning the adequacy of the provided graph. Some guidance is offered regarding the relationship between impulse and the area under the graph, but there is no consensus on how to proceed without clearer information.

Contextual Notes

Participants note the difficulty in interpreting the graph due to poor labeling and the absence of a visible figure, which complicates their ability to provide assistance. There is also mention of homework constraints that may influence the expected approach to the problem.

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A soccer player kicks a ball of mass 0.45 kg that is initially at rest. The player's foot is in contact with the ball for 0.005 s. The force of the kick is shown in the Figure. What is the impulse imparted on the ball?
http://psblnx03.bd.psu.edu/res/fsu/capalibrary/17Impulse/prob03.problem?symb=uploaded%2fpsuerie%2f6821119950c439fpsueriel2%2fdefault_1129569435%2esequence___14___fsu%2fcapalibrary%2f17Impulse%2fprob03%2eproblem

I know that I need to integrate to solve this problem, but how would I do that when I have no idea what the equation is?
 
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I can't see the figure.

Anyways, when integrating, what are you actually doing, and how could you do it graphically (às in derivating - tangent of the curve)?
 
I don't know how I can find the derivative when I don't know the equation. On the graph, the y-axis is not very well labeled, so I don't know how to find a tangent line.
 
To find the derivative from a function graphically, you draw a tangent at the desired point of the function.

Integration is calculating the area.
 
I just don't understand how I can integrate the graph, when I don't know the original function, and the graph isn't labeled well enough to get a close enough approximation of the force.
 
From what you're saying we can't really help you unless we see the graph
 
You would want to integrate that, but I'm not really sure how you would go about doing so.. you could estimate it pretty well by some meticulous eyeballing but if you need an exact answer I guess what you'd have to do is model the curve. It looks pretty quadratic to me..
 
Well, supposing it is quadratic, one gets the friendly formula: f(x) = -1.2e9x^2 + 6e6x. One can then work out the impulse. I don't think that's what the teacher wanted, it was probably meant to be an approximation.
 
Is there a way to figure out the final velocity? I know that the initial velocity is 0 since it's at rest. I'm thinking maybe I need to use final momentum- initial momentum for the impulse since the graph isn't very easy to read.
Any advice would be appreciated. Thanks
 
  • #10
Impulse = m * delta-v. The impulse is the area under the graph.
 
Last edited:

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