Mixed questions [Functions and Sequenzes & Series]

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Homework Help Overview

The discussion centers around questions related to functions and sequences & series, as the original poster prepares for an upcoming math test. Specific problems include finding the domain and range of a function, determining the conditions for a function to have an inverse, and calculating compound interest.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to find the range of a function from its graph and questions how to determine the defining equation of an inverse function. They also express uncertainty about solving a compound interest problem.
  • Some participants question the conditions necessary for a function to have an inverse and whether the function in question meets those conditions.
  • Others suggest checking the minimum and maximum values of a function to find the range and offer guidance on the correct formula for compound interest.
  • There is a discussion about discrepancies in the terms of a sequence and how to correctly express it.

Discussion Status

The discussion is ongoing, with participants providing insights and guidance on various aspects of the problems presented. There is no explicit consensus, but several lines of reasoning and approaches are being explored.

Contextual Notes

The original poster has indicated a time constraint due to an impending test, which may influence the urgency of the responses and the nature of the guidance offered.

Calavera
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Hi there,
I have a math test tomorrow and I have some questions from our books review sets that I haven't been able to solve yet. For now I only have questions on functions and Sequenzes & Series but it's possible that I might ad a few more later during the day. Here it goes...
---Functions---
1) I have the folowing graph, and with its help I'm supposed to find the domain and range. I can easily find the domain, but not the range. I don't actually know how to do it...
http://www.viitanen.se/q1f.gif
2) I plot the graph g(x)=x^2 + 6x + 7
Then I'm supposed to: "explain why g for x ≤ -3 has an inverse function g^-1".
To be honest I don't even know how to start...
3) Given h(x)=(x-4)^2 +3 where x≥3 I'm supposed to find the defining equation of h^-1.
I started on this by chaning the variables (changin place with y and x), and I finaly got it to: y^2 - 8y +16 = x-3. Ok, I can simplyfy it more but what should I do to the y^2? Should I use the abc formula, should I factorize it?
---Sequences & series---
1) Find the first term of the sequence 5, 10, 20, 40 which exceeds 10 000.
I wrote up the formula (5(2^n -1))/1 and plotted it on my gdc, then I got the answer that it was supposed to be U11, and when I put that into my formula and I got a right answer, 10235. The thing is that the key to the book says: "t12=10240"!
2)6000€ is invested, at 7% p.a. What is the compound interest after 5 years if the interest is compounded a) quaterly b) monthly.
I have really tried to solve this several times but haven't succeded. I don't simply know what to do...please help.
Ok, I know that there are a lot of problems but I would be really happy if someone could help me...soon if possible (test tomorrow). Thank you in advance!:smile:
 
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For #2, what condition must a function meet for an inverse to exist? Does g meet this condition for x <= -3?

edit: sign error

- Kamataat
 
Last edited:
A inverse has to be reflected in the line Y=X and it has to pass the horizontal line test ie only have one possible x value for each y value??
How am I supposed to know if g meets the condition?
 
Functions
1) what is the min value y can have ?
What is the max value y can have ?
The difference gives you the range of y.

3) don’t square out the (y-4) term. Instead take the square root of the other term (put a square root sign over it) and find y.

Sequences and Series
1) Did you notice that your answer and the book’s answer were out by 5, which is the value of your first term ?
Your expression for the nth term was out. You had Un = 5(2n – 1). It should have been Un = 5(2n-1)

2) the formula needed for compound interest is,

Pn = P0(1 + a)n

Where P0 is the original principle,
Pn is the principle after n intervals of getting interest added,
a is the interest rate for one particular time interval,
n is the number of time intervals.

You have two time intervals of interest. Monthly and quarterly. Get the right value of a for each time interval.
 
Calavera said:
A inverse has to be reflected in the line Y=X and it has to pass the horizontal line test ie only have one possible x value for each y value??
How am I supposed to know if g meets the condition?

The function is strictly decreasing for x < -3.

- Kamataat
 

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