How to Solve 4\sqrt{x-2} + 8=3\sqrt{x+6}-5 for x | Refresh Your Memory

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SUMMARY

The equation to solve is -4√(x-2) + 8 = 3√(x+6) - 5. To solve this type of irrational equation, square both sides to eliminate the square roots, which may require repeating the process. Careful arrangement of terms is essential to avoid introducing new square roots. Additionally, ensure that the expressions under the square roots remain non-negative, as this will affect the validity of potential solutions.

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  • Understanding of square root properties
  • Basic algebraic manipulation skills
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  • Ability to check for extraneous solutions
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Students preparing for CEGEP, high school algebra learners, and anyone looking to strengthen their skills in solving irrational equations.

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my teacher showed me how to solve this but she said we don't have to know it till cegep. id still like to know how to do it, can u guys help me refresh my memory?

[tex]-4\sqrt{x-2} + 8=3\sqrt{x+6}-5[/tex]

solve for x
 
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You can solve these kind of irrational equations by squaring both sides, it may be necessary to do so more than once.
You square because you want to get rid off the square roots, so it's necessary to carefully choose what to put on what side because you don't want to create new square roots as a result of mixed terms, or at least you want to minimize the number of those.

You have to be careful though, when squaring - the sign of both sides has to be the same and all expressions under the square roots can't be negative, these constraints give you conditions to test on your final answers - some may have to be cancelled.
 

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