This problem is driving me NUTS

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Homework Help Overview

The problem involves an object with a mass of 20 grams swinging horizontally with a radius of 2 meters, completing 10 rotations in 12 seconds. The question posed is about determining how much faster the object must be spun to increase the tension in the string by a factor of 4.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to relate the centripetal force to the tension in the string, noting that mass and radius remain constant while questioning how to adjust velocity to achieve the desired increase in tension.
  • Some participants question the clarity of the original poster's understanding of the relationship between velocity and centripetal force, particularly regarding the impact of squaring the velocity.
  • Another participant provides a calculation approach, discussing the period of motion and angular velocity, while suggesting a simpler method to arrive at the relationship between the initial and required velocities.

Discussion Status

The discussion includes various attempts to clarify the relationship between tension and velocity, with some participants offering calculations and insights. There is no explicit consensus, but a productive direction is noted through the sharing of calculations and alternative methods.

Contextual Notes

Participants are navigating the constraints of the problem, including the fixed mass and radius, while exploring the implications of increasing tension. The original poster expresses uncertainty about the calculations involved in adjusting velocity.

StaticShock
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Alright here's the problem. An object that has 20 grams of mass and is siwnging horizontally with a 2 meter ratius. it makes 10 rotations within 12 seconds.

the question is How many times faster would the stopper have to be spun to increase the tention of the string by a factor of 4?


now, i know Fc=M (V sq'ed)/R.

Mass stays the same, so does the radious(I belive) and the tention force is = to FC so fc has to be increased by a factor of 4 . So the only real thing to change is the V.

I just don't see how.
 
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i think you just answered your own question...

"how much faster does the stopper have to be spun" not how do you make it spin faster?
 
yes, but i don't know how to do it

Do I can't simply multiply V by 4 as the Square would throw it off
 
well i actually worked it out through the full calculations but there is a much simpler way i noticed afterwards.. Anyhoo

I started by finding the period of the motion

T = 10/12

Then the angular velocity
w = 2pi/T

then it was really plug and chug.

Fc = Mw^2r
Fc = 2.23 or somewhere around that, did in head soz.

Now you know your Force, multiply that by 4 and solve for V.

answer should be exactly 2x the intial velocity.
 

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