Minimum power that must be provided to the air-conditioner

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SUMMARY

The minimum power required for an air conditioner to maintain a home at 21°C while removing 25 kJ/h of heat from the interior is determined by the Coefficient of Performance (COP). The COP is defined as the ratio of heat removed (Q_c) to work input (W). To find the minimum power, one must calculate W using the formula W = Q_c / COP, where the COP is based on the efficiency of the air conditioning cycle. The most efficient air conditioner will yield the lowest power requirement.

PREREQUISITES
  • Understanding of thermodynamics, specifically heat transfer principles.
  • Familiarity with the concept of Coefficient of Performance (COP) in HVAC systems.
  • Basic knowledge of energy units, specifically kJ/h.
  • Awareness of air conditioning system efficiency metrics.
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  • Research the Coefficient of Performance (COP) for various air conditioning systems.
  • Learn about the principles of thermodynamics related to heat pumps and air conditioners.
  • Explore energy efficiency standards for HVAC systems.
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On a hot day, a Florida home is kept cool by an air conditioner. The outside temperature is 42.8C and the interior of the home is 21C.

If 25 kJ/h of heat is removed from the house , what is the minimum power that must be provided to the air-conditioner? Answer in units of kJ/h.


I'm preety stumped would the answer just be 25 kJ/h to compensate for the heat removed ?

Please help.
Thank you
 
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jdog6 said:
On a hot day, a Florida home is kept cool by an air conditioner. The outside temperature is 42.8C and the interior of the home is 21C.
If 25 kJ/h of heat is removed from the house , what is the minimum power that must be provided to the air-conditioner? Answer in units of kJ/h.
I'm preety stumped would the answer just be 25 kJ/h to compensate for the heat removed ?
Please help.
Thank you
You need to find the COP = Q_c/W to find W. The minimum power would be with the most efficient air conditioner. What is the COP of such a cycle?

AM
 

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