What Is the Maximum Inclination for a Cylinder to Roll Without Slipping?

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Homework Help Overview

The discussion revolves around a physics problem involving a solid cylinder rolling down an inclined plane without slipping. The original poster presents a scenario where a block of material begins to slide at an angle of 14.57°, prompting the question of the maximum angle for a cylinder made of the same material.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between the angle of inclination and the conditions for rolling without slipping, questioning the role of friction and the moment of inertia. Some participants attempt to derive the coefficient of friction and set up dynamics equations, while others express confusion over their calculations and results.

Discussion Status

There is an ongoing exploration of different approaches to the problem, with some participants providing hints and guidance regarding the relationship between acceleration and friction. Multiple interpretations of the problem are being discussed, and while some participants express understanding, there is no explicit consensus on the correct angle.

Contextual Notes

Participants note that the problem may hinge on the properties of the material and the geometry of the objects involved, with some suggesting that the angle of 14.57° might be significant in determining the maximum angle for the cylinder.

Punchlinegirl
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A block of a certain material begins to slide on an inclined plane when the plane is inclined to an angle of 14.57°. If a solid cyclinder is fashioned from the same material, what will be the maximum angle at which it will roll without slipping on the plane?

I really have no idea where to start on this problem since the only given is the angle. I know that the moment of inertia of a cylinder is (1/2)MR^2 if that's needed at all. Any hints?
 
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In what case does the cylinder slip (hint: friction)?
Another hint: total acceleration is the same as the tangential acceleration if there's no slipping.

(Would you happen to have the correct answer?)
 
Last edited:
I'm having trouble with a similar problem.

I tried finding the coeff of friction; got an arctan14.7 ...

Then I set up the dynamics equations of the cylinder, taking the center of mass as the center of rotation; Wx - friction = ma

And then I put in no slipping condition i.e a = (angular acceleration) X R.

I substitude (angular acceleration) with the relevant expression using Newton's second law in angular form.

I solve and then I get a very unlikely value of 89 degrees. Where am I wrong.
 
Kenny Lee said:
I'm having trouble with a similar problem.
I tried finding the coeff of friction; got an arctan14.7 ...
According to my calculations you should get a plain tan (not arctan).

Then I set up the dynamics equations of the cylinder, taking the center of mass as the center of rotation; Wx - friction = ma
And then I put in no slipping condition i.e a = (angular acceleration) X R.
I substitude (angular acceleration) with the relevant expression using Newton's second law in angular form.
I solve and then I get a very unlikely value of 89 degrees. Where am I wrong.

The rest sounds, if I understood everything correctly, fine.
 
Oh right. Yea, tan 14.7 degrees. Thanks.
okay now i get 38 degrees... dat bout right?
 
I see how to do it now. Thank you
 
Kenny Lee said:
Oh right. Yea, tan 14.7 degrees. Thanks.
okay now i get 38 degrees... dat bout right?
If you mean the problem in this thread (with the angle actually being 14.57), I get the same answer.

Punchlinegirl said:
I see how to do it now. Thank you
No problem :smile:.
 
romured question

Punchlinegirl said:
A block of a certain material begins to slide on an inclined plane when the plane is inclined to an angle of 14.57°. If a solid cyclinder is fashioned from the same material, what will be the maximum angle at which it will roll without slipping on the plane?
I really have no idea where to start on this problem since the only given is the angle. I know that the moment of inertia of a cylinder is (1/2)MR^2 if that's needed at all. Any hints?
i think that it's a romured question in which the answer is 14.57 degree because friction doesn't pertain to shape of the block or how much is the surface of that
i think the answer is that
 

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