Recent content by 037810

t's would cancel out in that case..

because I'm trying to solve this question: find parametric eq of a linethat intersects both lines, [x,y,z]=[4,8,-1]+t[2,3,-4] [x,y,z]=[7,2,-1]+s[-6,1,2] at 90 degrees. So with direction vectors, i cross multiplied to get [1,2,2]. I just need to know the point that the line goes...

yah but these two lines are already skew? so the third equation does not satisfy. if the screw lines of the diff planes come down to make just one plane, they'd obviously have an intersection right? how would you find that intersection?

For example [x,y,z]=[4,8,-1]+t[2,3,-4] [x,y,z]=[7,2,-1]+s[-6,1,2] I did... x=4+2t=6s y=8+3t=2+s z=-1-4t=-1+2s and got t = -6/5 and s=12/5 so since no interception and not parallel, it's a skew line. But if they were in the same plane.. how would you find the...

hmm... but drawing wise, they are the same?

Okay, let's say there's vector a,b and c What would be the difference between projection of c on a and b and components of c along a and b I thought they were the same... thanks.

hmm! thank you. After thinking about it, i came up with this idea: Although the particle will still be in a circular motion (because magnetic field is uniform and e.field doesn't change the strength of it) it will move in the direction of the e.field? so it travels alongs the e.field...

A question: is magnetic field just a simple plane 2-d plane ? or streams of it making an actual volume of something. (kinda like a pipe) my brain hurts inside :(

I do see how the particle in circular motion is perpendicular to the m.field. (thinking 3D wise) but no, i do not know why the particle is moving in a circle.. :( This is leading me to think in so many different possibilities, which all seem to make sense due to my low knowledge haha.

ohhh... yes I can. Ahh shoot. Your explanations helped me quite a bit haha, hm...so If the e.field is being added in the same direction as the m.field, and the e.field pushes the charged particle along the m.field (depends on +/-).. does that mean, the circular path will either...

and also... a moving charge produces an electric field and magnetic field right?... this is confusing me even more. so the moving particle itself produces m/e fields that effect itself too?

hmm.. I thought being in a circular motion negliges perpendicular or parallel, and is parallel at 2 pts and perp. at 2pts.. sdfjghsdlkfjgdskjfhdsj

I don't know how to show work for this one, as it's not really a calculation probrolem (if it is, I'm not really sure which equation to use), but basically I drew a particle going in a circular motion. with mag fields going across it. since more are being added, I drew the exact same picture...

Homework Statement A charged particle is moving in a circular path under the influence of a uniform magnetic field. Describe how the path will change if an electric field is added, in the same direction as the magnetic field. Homework Equations The Attempt at a Solution Well...

i solved finally, thank you.