Recent content by 44r0n0wnz

Al is right. In the first part, energy is not conserved because the collision is inelastic. After the collision, the block moves right after the bullet stops, making this part of it elastic. Solve by using conservation of momentum for the first part and conservation of energy for the second part.

NvM. I got it. Law of cosines and sum difference formulas. Ø1 + ø2 = 90, so it is safe to assume that : cos(Ø1 + ø2) = 0 since cos(90) = 0. Now, for the actual proof, start by using the formula for conservation of kinetic energy: K1i + K2i = K1f + K2f. After simplifying...

I understand everything except what is in bold. First, you are finding the momentum along the X. Then finding the momentum along the Y. Then somehow combine them in the equation for the conservation of energy. I have all of that already, but I don't understand the combining itself and don't...

Could you please describe the work in more detail? I understand the entire concept entirely, and even matched up with a lot of the math you did, but I didn't understand the combining you did in the middle and how the angle 90 just appeared out of nowhere.