Recent content by aalberto

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    About self-measurement in entangled system

    Dear mfb, Yes, I thought that the placing of wrong battery in δ could be considered a kind delayed measurement made by the dealer, that could influence the outcomes of X and Y, as a kind of “hidden variable”. But that was my mistake, as you write, so if X will find δ uncalculating, the...
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    About self-measurement in entangled system

    Dear mfb, I will do my best to explain the point. The experiment was arranged by two observers X and Y that bought the two nanocomputers by a not very honest dealer that guarantees that the batteries had the same life. So both X and Y were unaware of the battery life of δ, but aware of...
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    About self-measurement in entangled system

    Dear Mtf, Regarding the impossibility to have the two nanocomputer calculating and uncalculating together, you are right, I made a mistake, probably I should have to use two photons having the same initial polarization, that in superposition would results |ψ>= 1/ √2 |1V>|2V> + 1/√ 2|1H>|2H>)...
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    About self-measurement in entangled system

    Dear Bill, You are right, I apologize, I will try to re-arrange the experiment trying to meet your requirements: We have two nanocomputers δ and β able to do, many operations, including calculations of problems stored in their memory. Everything at extremely low temperature in an isolated...
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    About self-measurement in entangled system

    As I wrote before, is not my main goal to realize, now, the entanglement experiment. All the thought experiment is only to illustrate my question, so, please, consider for a moment that the two microcomputers are really entangled, and described by the equation |ψ>. After the death of δ, for...
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    About self-measurement in entangled system

    For Schroedinger's hammer, I mean an extremely small device able to cause the lost of consciousness without kill the microcomputer. Regarding the consciousness, I am taking it in the simplest way, i.e. the subjective esperience, that you have when you are awake and you not have when you are...
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    About self-measurement in entangled system

    Obviously the system is isolated as I wrote in my first letter. The entanglements should be obtained aproximately in that way: 1) source of entangled photons 2) two polarizers 3) two Schrodinger's hammers (one per microcomputer) carefully calibrated, that, if the photon pass through the...
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    About self-measurement in entangled system

    Dear Bill, Thank you for accepting to discuss my example with a Collapse interpretation. Yes, the death of the microcomputer δ is determined by the battery. This is the motive of the choice of the consciousness among the many attributes of the microcomputers. But the two...
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    About self-measurement in entangled system

    Dear Bill, Thank you for your answer. My example is not strictly related to the Von Neumann/Wigner interpretation, I have written consciousness, but it could be every other attribute of microcomputers. Thank you for your book suggestion. Personally I am more inclined to Collapse point...
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    About self-measurement in entangled system

    I am trying to understand something about the problem of self-measurement in entangled system, I will try to do an example, please help me: If we have an isolated system with two entangled, conscious, microcomputers, one, δ with 1 hour cell, and the other β with a 10 hours cell. Here I am...
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