Recent content by Abner

When calculating to find the first 5 coefficients, i get everything wrong except for the first one which = 6.

Honestly, i don't understand how to solve this problem at all. I spent at least 3 hours in this problem, that i don't know what I'm doing.

i was just following some examples from the book.

\frac{6}{1+49x^2} = \frac{6}{1-(-49x^2)} = \displaystyle \sum_{n=0}^\infty 6(-1)^n (49x^2)^n = \displaystyle \sum_{n=0}^\infty 6(-1)^n 49x^{2n}

Homework Statement I have this function f(x) = \frac{6}{1+49x^2}, and i suppose to represent this function as a power series \displaystyle f(x) = \sum_{n=0}^\infty c_n x^n. Then i need to find the first few coefficients in the power series. Homework EquationsThe Attempt at a Solution After...

ok that makes sense. Thanks for the replies and the help.

So, when one point is convergent we use the closed interval, and open if it diverges?

Yes, the answer is correct but i just noticed that i enter the interval in the wrong notations. It supposed to be (-17/4,-15/4]. I just don't understand why one interval is open, and the other one is closed.

Homework Statement I have this problem to consider the power series, \sum_{n=1}^{\infty}\frac{(-4)^{n}}{\sqrt{n}}(x+4)^{n} So, i need to find the R and interval of convergence. Homework Equations The Attempt at a Solution This is what i did: \lim_{n\rightarrow \infty}...

My name is Abner, and I'm a new member in this forum. I'm a senior at Cal State Dominguez Hills in Carson, CA, and i will be graduating with a BS in Computer Science.