Recent content by abpandanguyen

Okay, that makes sense now. Thank you very much!

Okay, so I'm basically adding the pressure at the top and the bottom, then dividing it by two (averaging it)? That makes sense if its right >.>.

I am still slightly confused ;_; I think of my idea of how pressure is distributed is skewed.

Okay so now I am doing this 1000 x 9.80 x 2.10 to get Pascals (N/m2 = kg/(m)(s)2) I am then multiplying this number by the respective areas of the sides and ends to get Newtons but if my original answers were within 10% of the correct answer, then these are definitely way out of the ballpark.

Sorry... I am not really following you. I think I'm having a hard time picturing the setting in question. I am thinking of this question as it was asking for the pressure the water had on the side as in a rectangle. Am I thinking of this right?

Homework Statement A swimming pool has dimensions 28.0 m 12.0 m and a flat bottom. When the pool is filled to a depth of 2.10 m with fresh water, what is the force caused by the water on the bottom? On each end? (The ends are 12.0 m.) On each side? (The sides are 28.0 m.) Homework...

thank you! want to help me on my other recent post? >_<

I think I am getting confused by the y=sqrt(x), y = x etc. so having that aside, if they all start from the same height, that means they should all have the same initial potential energy and thus same final kinetic energy and given this, when you write the equations out, they all have the...

here's one example 1. mgsqrt(x) = (1/2)mv2 sqrt(2g(sqrt(x))) = v 2. mgx = (1/2)mv2 sqrt(2gx) = v

o whoops I meant to put that as x^2 I solved for v using conservation of mechanical energy but all my v values came out rather different still. I think I might be doing it wrong...

Homework Statement Consider 4 frictionless slides described by the equations (1) y = sqrt(x), (2) y = x, (3) y = 2x, (4) y = x2. If you start at rest at y = h and slide down to y = 0, which statement regarding your speed v at y = 0 is correct? Homework Equations (1/2)mv2 = KE mgh =...

if it was counteracting gravity, doesn't that mean it would be - mg? I don't think I'm quite understanding here.

Homework Statement A bullet of mass m = .010 kg and speed v passes completely through a pendulum bob of mass M = 1.2 kg. The bullet emerges with a speed of v/2. The pendulum bob is suspended by a rigid rod of length l = 0.50 m and negligible mass that can pivot about the center point...

yeah, i just needed to write the equations out instead of just thinking in my head thanks!

Homework Statement A mass weighs 20 N at the surface of a planet of 3000 km radius. What is the mass's weight when it is in orbit 3000 km above the surface of the planet? Homework Equations F = (Gm1m2)/r2 (well... not really) Ug = mgy The Attempt at a Solution I don't even know...