Recent content by Abs321

Oh, I've just found an answer. It's (6 ∥ 5+1∥ 4+2) ∥ 2 Was your solution simpler?

And this is where I stop. Is it possible to combine 2 ohms in 2 parallel branches from remaining 5 resistors? Or do we need 3 branches?

Oh, I suppose there could be two parallel circuit from 2 ohms and another sub-circuit totally of 2 ohms and so on, I understand how these laws work, but I can't construct such circuit. Just playing on with resistors.

Homework Statement We have 1Ω, 2Ω, 2Ω, 4Ω, 5Ω and 6Ω resistors. We have to make a circuit with all of them and total resistance must be 1 ohm. Homework Equations Parallel: 1/R1+1/R2=1/R In series: R1+R2=R The Attempt at a Solution I have only made a circuit from 4 resistors: 1 ohm and 2 ohms...