Recent content by Academic

I don't see much of a point in getting the masters, unless you have things you want to learn. In my experience a masters in physics is just about as unmarketable as a B.S. in physics.

@ gravenewworld, Take care not to confuse having a physics degree with being a physicist. Most people with physics degrees would not be considered a physicist in that list. Im my experience, physics without a PhD is a fairly useless degree in that it is not much more marketable or...

I have a BS in physics and now work in a restaurant. I would figuratively kill for a crappy dead end tech job.

Let me chime in with a dissenting opinion; I am not smart enough to do physics and probably shouldn't have ever tried it. It is still my favorite subject, and I like reading about it as a hobby. But shooting for it as a career goal was a terrible mistake in my case, because I fell short and...

I also dropped out of high school. I went back for physics in my mid-twenties. It went good, got good grades and got my degree. But I kinda of wish I would have done a trade because as much as I like the personal growth and philosophic knowledge that the physics degree provides, I would also...

How much extra food is this going to cost me? :p

Because we have look far and wide, and only found two. (or three if you count neutral :) )

Oh right. The total angular momentum is zero, but the spin angular momentum could be non-zero. That means I could have states, \mid -, \uparrow \rangle \otimes \mid +, \uparrow \rangle \mid -, \downarrow \rangle \otimes \mid +, \downarrow \rangle So my state is a linear combination of...

A vibrational frequency of c is impossible period. C and frequency don't have the same units, you cannot compare a speed to a frequency.

Well, there must be a component of the E field parallel to the wire inside the wire right? Otherwise there would be no current. Then the boundary condition at the edge of the wire says that the E field outside the wire also has a parallel component.

Hello, Basically my problem is trying to understand the electric field outside of a current carrying wire. My first thought is that it is zero, but now I am not sure. The boundary condition of the electric field says that the parallel component inside and out must be the same, so this means...

I can't figure out what the two other states you mention are. Is it these? \mid -,\uparrow \rangle \otimes \mid +,\downarrow \rangle \mid -, \downarrow \rangle \otimes \mid +,\uparrow \rangle If so I don't really see how this is different than the two...

I think this statistic is kind of a misrepresentation. Most people who get PhDs in an astronomy related field do not become astronomers. So most people with a PhD in astronomy are not counted in that stat. Similarly, I would expect AIP's survey to be skewed towards the high wage earners...

Homework Statement Positronium is formed by stopping anti-electrons in matter. It is found that the bound system is formed in two distinct states, both of which have orbital angular momentum $ L = 0 $ . Consider the possible spin configuration of this system, to determine the expected total...

That usually means the principle quantum number is 1.