Recent content by ActionFrank

Yes the range will be the horizontal distance. Since projectiles move horizontally at a constant velocity, it is simply calculated by multiplying the x-component of the velocity by the time of flight. x=v(x)*t where v(x) means the x-component of the velocity. v(x) = v*cos(theta) x = the range...

Based on my reading of this problem it seems that the correct answer is the one that you hit on at the end, that there is no applied force in this problem.