Recent content by Addie M

That makes a lot more sense. Thanks so much!

I think I might have been overthinking this way too much. Is the answer just 4Fd? Since the torque of T1 is Fd , T2 is 3Fd, and they are rotating in the same direction?

Well thats just the sqrt of d^2 + (d-x)^2 which is a messy value. But wouldn’t whatever that value is multiplied by sin of our unknown angle just be d?

For either method wouldn’t I need the value for the radius (diagonal line from pivot to the point where 3F starts)? The problem I’m having is I still have no idea how to get that radius value. Like I said, I put in d-x for the side I didn’t know, but the value I got for the radius is a mess and...

So would that perpendicular line be a diagonal line from the pivot point to the point where the 3F starts or a horizontal one from the pivot point to the side where the 3F is? I assume it’s the first one but I have no idea how to find the value of the diagonal line (radius) since I only have the...

We haven’t discussed anything about sliding vectors or lines of action yet in class, so I’m really lost on how I would use that in order to solve this problem and find the radius of T2 in terms of d.

Yes, I’m trying to find the net torque on that exact pivot point. Could you also explain sliding vectors to me a little more. From what I understand, I can just move the entire pivot point down and the radius for T2 would be d, but then I would run into the same problem I did originally with T1...

What would I enter in for radius though since I don’t have any actual measurements only variables?

Well I know that the angle is found from the force and lever arm, I’ve used that for some more real work esque problems with ladders and diving boards. I don’t see how I could use that here with the radius since I can’t even find that.

So I started by just figuring out what forces are going to have torque. I know the one heading straight down from the pivot won’t have any and the one going at an angle from the pivot won’t be included in the net torque since it’s at the pivot. The rest of the forces have torque and they are...