Recent content by adk

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    Power Problem: Calculating the Power Required to Push a Train Up an Incline

    If we use the first equation: F=m*a = (110,000)(9.81) = 1079100 P=1079100*20km/hr=21582000 N Is this correct? Where do you go from here?
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    How Do You Determine the Third Force in a 3-Force Equilibrium Problem?

    how do we know the forces will add up to 0? would the equilibrium equations be: 40sin(60)=34.64 30cos(60)=15
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    How Far Does a Particle Travel in an Equilateral Triangle with Mixed Motion?

    i solved this equation: (10)(5) + (1/2)(9.81)(5)^2 = 172.625 where does this fit in though - not really sure what i was solving for?
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    Power Problem: Calculating the Power Required to Push a Train Up an Incline

    Homework Statement What power is required to push a train weighing 110,000 kilograms up an incline of 1 in 100 at 20 kilometers per hour, all frictional resistances being neglected? Homework Equations P = ΔE/ ΔT The Attempt at a Solution This is the only power equation we...
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    Kinematic Distance Problem? Can't Tell

    still not sure where to begin as far as equations go. how do we know it will be 4 times less than the earth?
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    How Far Does a Particle Travel in an Equilateral Triangle with Mixed Motion?

    no figure or coordinate system was given unfortunately. what do you mean by solve for adjacent sides? thanks.
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    How Far Does a Particle Travel in an Equilateral Triangle with Mixed Motion?

    Homework Statement A particle moves from rest and has impressed a uniform velocity of 10 meters per second parallel to one side of an equilateral triangle, and a uniform acceleration of 10 meters/sec2 parallel to an adjacent side of the triangle. Find the distance of the particle from its...
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    Kinematic Distance Problem? Can't Tell

    Homework Statement An observer on the Earth observes the angle subtended by the diameter of the moon to be 0.009199 radians. If the moon is 234,800 miles away, what is its diameter? Homework Equations The Attempt at a Solution Not quite sure where to begin with this one. I think it...