Power Problem: Calculating the Power Required to Push a Train Up an Incline

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SUMMARY

The power required to push a train weighing 110,000 kilograms up an incline of 1 in 100 at a speed of 20 kilometers per hour can be calculated using the formula P = F × v, where F is the force and v is the velocity. The force can be determined using F = m × g, resulting in a force of 1,079,100 Newtons. When this force is multiplied by the velocity (converted to meters per second), the power required is calculated to be 21,582,000 Watts. This calculation neglects frictional resistances and focuses solely on gravitational forces acting on the incline.

PREREQUISITES
  • Understanding of Newton's Second Law (F = m × a)
  • Knowledge of gravitational acceleration (g = 9.81 m/s²)
  • Familiarity with power calculations (P = F × v)
  • Ability to convert units (e.g., kilometers per hour to meters per second)
NEXT STEPS
  • Learn about calculating forces on inclined planes using equilibrium considerations.
  • Study kinematics to understand how to calculate time taken to reach a certain height.
  • Explore the implications of friction on power calculations in real-world scenarios.
  • Investigate different methods for calculating power in mechanical systems.
USEFUL FOR

Students in physics or engineering, particularly those studying mechanics, as well as professionals involved in transportation engineering and locomotive design.

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Homework Statement



What power is required to push a train weighing 110,000 kilograms up an incline of 1 in 100 at 20 kilometers per hour, all frictional resistances being neglected?

Homework Equations


P = ΔE/ ΔT


The Attempt at a Solution



This is the only power equation we discussed:
P= ΔE/ ΔT = (m)(g)(h)/t
This doesn't really fit with the data given b/c there's a velocity. Also
I don't know how to express that ratio of 1 in 100 in the equation.
 
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adk said:

Homework Statement



What power is required to push a train weighing 110,000 kilograms up an incline of 1 in 100 at 20 kilometers per hour, all frictional resistances being neglected?

Homework Equations


P = ΔE/ ΔT


The Attempt at a Solution



This is the only power equation we discussed:
P= ΔE/ ΔT = (m)(g)(h)/t
This doesn't really fit with the data given b/c there's a velocity. Also
I don't know how to express that ratio of 1 in 100 in the equation.
the power required to push the train at constant speed may be determined from Power = Force times velocity, where the force is the pushing force which you can calculate from equilibrium considerations. Or you can calculate that force and use P= work/time, where work is the pushing force times the distance traveled in the direction of the force (letting h=1 m, find the distance traveled up the incline to reach the 1 m high mark using the 1:100 slope), then you can calculate the time it takes for the train to reach a point 1 m high using kinematics. Or else use your listed equation, finding t in the same manner...it all leads to the same answer.
 
PhanthomJay said:
the power required to push the train at constant speed may be determined from Power = Force times velocity, where the force is the pushing force which you can calculate from equilibrium considerations.

If we use the first equation:

F=m*a = (110,000)(9.81) = 1079100
P=1079100*20km/hr=21582000 N

Is this correct? Where do you go from here?
 

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