Recent content by Adrian Pete

oh okay, because cos 180 is -1. okay Sir. Thank you for the help ^ _ ^

since there is no acceleration therefore, F - fk = ma = 0 F = fk ? so F is basically fk? so work done by F is the same as work done by fk?

force = m * a? so a is 0 because it moves at constant velocity? so force = 30kg * 0 m/s^2 a) f = 0N so work is w = f d cos theta so, w = 0 * 4.5m cos 0 so b) w = 0J = work done by the worker?

a) work must the worker apply = :( b) work done by the force = :( c) work done by friction = Wf = 73.5N*4.5m d) work done by gravity = Wg = 294N*4.5m e) work done by normal force Wn = 294N*4.5m only these Sir :( can't figure out to solve a) and b)

5 forces acting on it Sir

Homework Statement Problem # 1 Homework Equations Work done by several forces w=f * d cos theta w=mg n=w The Attempt at a Solution I can't figure out how to solve a) and b) NOT SURE: so my attempt a) f = mg = 30kg*9.8m/s^2 = 294N =magnitute of the force must the worker apply.(NOT SURE)...