Recent content by Adriane Baun

Oh i see i misread the problem so it should be Efficiency = 1 – 400J/1000J = 0.6 Then 0.6 = 1 – Tc/Th = 1 – Tc/300K Tc = 120K

Homework Statement A Carnot engine absorbed 1.0 kJ of heat at 300 K, and exhausted 400 J of heat at the end of the cycle. What is the temperature at the end of the cycle? Homework Equations The efficiency of a Carnot engine is given by the formula Efficiency = 1 – Qc/Qh = 1 –...