Did you mean to use 300 J for QC? The problem statement gives 400 J.Adriane Baun said:The Attempt at a Solution
Efficiency = 1 – 300J/1000J
= 0.7 = 70%
0.7 = 1 – Tc/Th = 1 – Tc/300K
Tc = 90K
Is it correct?
A Carnot engine is a hypothetical engine that operates on the Carnot cycle, a theoretical thermodynamic cycle that represents the most efficient way to convert heat into work. It serves as a model for the maximum possible efficiency of any heat engine.
A Carnot engine consists of a working substance (such as a gas) contained within a cylinder. The working substance is alternately heated and cooled, causing it to expand and contract, which drives a piston to do work. This process is repeated in a cyclical manner.
The Carnot efficiency formula is: efficiency = (Th - Tc) / Th, where Th is the temperature of the heat source and Tc is the temperature of the heat sink. This formula represents the maximum possible efficiency for a heat engine operating between two temperature extremes.
The Carnot engine is considered to be the most efficient because it operates on a theoretical cycle that eliminates all sources of inefficiency, such as friction and heat loss. This means that it represents the maximum possible efficiency that can be achieved by any heat engine.
The efficiency of a Carnot engine is affected by the temperature of the heat source and heat sink, as well as the type of working substance used. It is also influenced by the Carnot cycle itself, which involves reversible processes that minimize energy loss.