Recent content by aero13

Ok so I set 1/15y^2 + 6y + 5 equal to 4. Ended up with 1 = 4(15y^2 + 6y + 5) so 1 = 60y^2 + 24y +20. Do I factor it from here?

Homework Statement Find (f−1)'(a). f(x) = 5x^3 + 3x^2 + 5^x + 4, a = 4 Homework Equations I'm not entirely sure but I assume I have to use d/dx(f-1) = 1/f '(f-1(x)) The Attempt at a Solution So far I switched y and x. Found dx/dy to be 15y^2 + 6y + 5. Then I switched dx/dy to...