But since it has an uniform charge distribution, wouldn't it be an uniform electric field?
I understand that with calculus, after deriving, it would be lambda/2pie0 * ln (0.10 - 0.05), but still can't figure out how to do without it.
In order for q1 to be in equilibrium to the other two, both others equilibrium with q1 would have to be equal, and since 5q is 5 times bigger than q and opposite, it's safe to say that it'd have to be to the left of q to be distant enough for equilibrium?
kq1q/(distance )**2 = kq15q/(distance +...
Homework Statement
An electric field is created by an uniform linear charge with a linear charge density is 40 nC/m. Find the potential difference between the two points, one of which is situated 5 cm from the line charge and the second at 10cm.
Two charges, q and -3q, are situated at a...