Recent content by agalea91

You're right, the full radial equation as I have it is this, T=mgcos(theta)+mL(dtheta/dt)^2 My hope was that in integrating the right half independently of the tension then I could make a substitution (from the result of that integration, into the full equation) that would allow me to have...

Im solving for the tension in a pendulum, right now I am equating the radial accel with the force of gravity to try and integrate to something with a theta-not (representing the max amplitude of the pendulum) and theta (t). Hope that makes some sense

Homework Statement im not sure the elegant way to put it, i need to integrate this somehow (ie, throw over the dt and integrate each side) but that squared is really tripping me up. is there a trick i should be using? -g(cos(x))=r(dx/dt)^2 Homework Equations The Attempt at a...