Recent content by Agent47

I agree that the way you have explained is much simpler, ill ask my lecturer on what his method is. Thanks for your help.

I worked out R= 118K ohm and C = 1.37x10-8. I checked by putting the values back into the equation and got the correct z. I guess i don't understand what my lecturer is going on about finding the common denominator etc.

If i do 1/z i would get 8.485x10-6 +j 4.323x10-4. I am not sure on how i would get and RC from 1/z = (1+jwRC)/R.

Homework Statement The circuit is a Parallel RC Z= 105KΩ∠-27 and Frequency is 50 Hz. I was given the following information and hints. 1/z = 1/R + jwc I need to find the common denominator of 1/R + jwc, Invert it to find z and simplify Z into one real and one imaginary part...

I want to thank you both for your help.

If i do 1/z i would get, 0.000008485 +j0.000004323 but I am still not sure where R and C would come from.

Homework Statement A RC parallel circuit with an impedance of Z = 105000 Ω ∠ -27 and frequency of 50 Hz. Homework Equations I need to find out what the R and C values using the information given. The Attempt at a Solution I know the impedance for a parallel RC can be calculated...