Recent content by AhmirMalik

Oh.. then you just have to use this; \vec{\nabla}\times \vec{B}=\mu_{0}\vec{J}+\mu_{0}\epsilon_{0}\frac{\partial \vec{E}}{\partial t} Since you don't have any currents, so first term on the right hand side is zero, so you are left with; \vec{\nabla}\times...

Why do you say that E_{z}=0 and then E_{z}=(\omega B_{0})/k. You can't say that the z component of electric field is zero and non zero at the same time... clear that confusion then I'll solve your problem.

The total energy of the system has to be conserved. That means, the total initial energy must be equal to the final total energy. \frac{m(v_{i})^2}{2}+mgh_{i}=\frac{m(v_{f})^2}{2}+mgh_{f} where \frac{m(v_{i})^2}{2} is what you are looking for.

Why don't you just aply the conservation of the energy? E_{i}=E_{f}

Ok, thank you !

Thank you for replying. Actually, I knew that. And that's where I'm stucked. Could you please develop a bit more?

Homework Statement Given H=\frac{1}{2m}\left[ \vec{P}-q\vec{A}\right] ^{2}+qU+\frac{q\hbar }{2m}\vec{\sigma}.\vec{B} ..(1) show that it can be written in this form; H=\frac{1}{2m}\left\{ \vec{\sigma}.\left[ \vec{P}-q\vec{A}\right] \right\}^{2}+qU ...(2) Homework Equations [/B] In my...