Recent content by Air_Gear

Thank you! The problem didn't specify, but from the wording I would imagine that Qy was brought in by Q alone. Is the math correct now? Wx = (k * Q * Qx)/a => Wx = (k * 2Q^2)/a

Homework Statement A charge Q is at the origin. A second charge, Qx = 2Q, is brought to the point x = a and y = 0. A third charge Qy is brought to the point x = 0, y = a. If it takes twice as much work to bring in Qy as it did Qx, what is Qy in terms of Q? Homework Equations My main problem...