So then
Impulse = ∆Momentum
∆Momentum = mv(Initial) - mv(final)
So the v(final) should be negative (my coordinate plane being down as the positive direction)
then
∆Momentum = (2.4kg)(2.5m/s) - (2.4kg)( - 1.5m/s)
which gives me
∆Momentum = 6 + 3.6 = 9.6
Thanks!
Impulse -- I am suspecting a wrong answer on the key.
A 2.4-kg ball falling vertically hits the floor with a speed of 2.5 m/s and rebounds with a speed of 1.5 m/s. What is the magnitude of the impulse exerted on the ball by the floor?
* 9.6N/s
* 2.4N/s
* 6.4N/s
* 1.6N/s
* 1.0N/s...