Recent content by akk

Thank you very much . So basically the factor 1/{h^3} is not a normalization constant. It the volume element of a quantum state in phase space. and we do not get it by integration. The Fermi-Dirac distribution function is \begin{equation} f(E)=\frac{1}{e^\frac{{E-E_{F}}}{k_{B}T}+1}...

Fermi-Dirac distribution function is given by f(E)=(1)/(Aexp{E/k_{B}T}+1) here A is the normalization constant? How we can get A? E is the energy, k_{B} is the Boltzmann constant and T is the temperature. thank you

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ASTROPHYSICS PROCESSES by HALE BRADT Massachusetts Institute of Technology,

Thanks,, i may be wrong, but i found in many books that its normalization constant is 2\{h}^{3},,here 2 is due to two possible vales of the fermion spin and h is the volume of a quantum state in the phase space.

, here A is the normalization constant for Mazwellian distribution. The normalization constnt for Fermi-Dirac is 2/{h}^{3},,where h is Planck's constant. but i don't know how to normalize..don't know formula

How to find the normalization constant of Fermi-Dirac distribution function.

Thanks

and i am feeling good to be part of a nice forum.

n=\int^{\infinity}_{infinity}f(E)d^{3}E i am using this formula,,,but i could not normalize it?Any idea or hint