ok, i just noticed where i went wrong.
Using f(0)=1
I think its:
(-s-12)/(s^2 +4)
Is this correct?
Thanks.
I like that you don't just tell me the answer, it helps me improve and makes you feel better when you have done it yourself.
Normally they use 1.
But i can't get it correct if i use that.
Unless i am doing something wrong.
here is how i am doing it:
3(-1+sF(s))-F(s)
3-3sF(s)-F(s)
(-3s-1)*F(s)+3
((-3s-1)*s/(s^2 +4)) +3
(-3s^2 - s + 3s^2 +12)/(s^2 +4)
= (-s+12)/(s^2 +4)
thanks,
How do you work out what f(0) is?
i thought it was f(t) at 0. And 0 on the cos2x graph is 1, isn't it?
Or am i incorrect on how to work it out.
On the first question i get to here:
4(s/((s+2)^2 +4).
ok i just worked backwards and i think the answer is:
4e^(-2t) * (cos2t-sin2t) is this...
Ok i have two questions, one i am unsure of and one i don't have a clue how to correctly find it.
Homework Statement
You have to work out the inverse function of:
4s/ s^2+4s+8
The Attempt at a Solution
I think the answer is:
4e^(-2t)*(cos2t+sin2t)
Is this correct?
Homework...