Recent content by Alexandra

That 's a very good trick, thanks vela!

Now I feel very stupid...Thanks epenguin!

Sorry, I had two mistakes. When I reference the equation (3), I meant equation (2). And the lower index on the integral (3) is 1, not 0.

I split this to get \begin{equation} \int ^{\infty} _{0} \dfrac{e^{ax}}{(1+e^{ax})(1+e^{bx})} \ dx - \int ^{\infty} _{0} \dfrac{e^{bx}}{(1+e^{ax})(1+e^{bx})} \ dx \end{equation} Then I tried to solve the first term (both term are similars). The problem is that I made a substitution (many ones...