Recent content by Alfredomaximun

Hi Berkeman, I changed the image and did it above but it doesn't seem to be correct The original image was this

Summary: ##M=3\left(n-1\right)-2j_1-j_2## Hi, I'm trying to get the degrees of freedom of a can crusher. So substituting I get ## \begin{array}{l}M=3\left(n-1\right)-2j_1-j_2\\ n=5\\ j_1=5\\ M=3\left(5-1\right)-2\cdot 5-0\\ M=2\end{array} ## And I would think it would be 1