Recent content by aliinuur

I mean exp(-E/kT) is Boltzman distribution

As far as I understand kT defines scale of Boltzman distribution, i.e. avg. energy and Boltzman distr. are the same thing. And for me, Planck's move to find avg. energy different from 1/2kT from Boltzman distr. is like 1+1=2, 2-1=3.

$$\lambda_x = \frac{L}{n_x} , \lambda_y=\frac{L}{n_y} . \lambda$$ does not fit the cube as integer. In the figure $$n_x=4, n_y=3$$

yeah, here is my wrong. Thanks!!!!!!!!! Now it fits perfectly!

Here, v=c/2. 1. When the vertical photon (photon V) hits ceiling of the box, thus traveling distance R, the emitter travels distance $$\frac{L_0}{2}$$ along the x-axis, the horizontal photon (photon H) also travels distance R along the x-axis, so that it is P-distance ahead of where it must meet...

i've posted my derivation as reply above

here is my calculations for v=c/2. Diagonal arrows - path of the vertical photon, horizontal arrows - path of the horizontal photon, both photons travel distance 2*R=2*L*sqrt(1+1/4). I find contracted length by subtracting x1(path of the emitter when horizontal photon hits the wall) from the...

I tried to use square box with two perpendicularly oscillating photons to derive length contraction formula. Photons are emitted, reflected from box walls and absorbed simultaneously from the box's point of view. If the box have some velocity v, then assuming photons are still emitted and...

heat of gas A goes to kinetic energy of the piston A, heat transfered via pistons, but there is no external work or something like that

its dipole moment has equal chance of pointing in any direction :)

you are right, even the hydrogen atom is a dipole, i.e. has a electric field

yeah, you got it right

yeah, how is magnetic field relevant to my question? you have started talking about magnetic field

there is electric field though.