Recent content by alphaneutrino
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Projector Operator: P^2, Eigenvalues & Eigenfunctions
Thank you Compuchip! I am asking about P. Yes, I know that P^2|x> = |x> which is not equal to p|x>. So it is not projection operator. My next confusion is can I write |-x> = -|x> ? How can we calculate the eigen value and eigen function of P- alphaneutrino
- Post #5
- Forum: Advanced Physics Homework Help
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Projector Operator: P^2, Eigenvalues & Eigenfunctions
An Operator is defined as P|x> = |-x>, 1. Is P^2 a Projector operator? 2. What are the eigen value and eigen function of P?- alphaneutrino
- Thread
- Operator Projector
- Replies: 8
- Forum: Advanced Physics Homework Help
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How can I show that trace is Invariant under the change of basis?
thanks CompuChip- alphaneutrino
- Post #3
- Forum: Advanced Physics Homework Help
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How can I show that trace is Invariant under the change of basis?
How can I show that trace is Invariant under the change of basis?- alphaneutrino
- Thread
- Basis Change Change of basis Invariant Trace
- Replies: 3
- Forum: Advanced Physics Homework Help