Recent content by alsy

  1. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    m/s2
  2. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    ok a= -1.6 m/s
  3. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    its correct now a=1.6 m/s
  4. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    0=4.8+3a a=1.6 m/s
  5. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    u=initial velocity a=acceleration t=time 8-4=4 constant velocity
  6. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    0= 4.8+ a(3) 0=4.8 +3a a=-1.6 m/s
  7. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    0= 4.8+ a(4) 0= 4.8 +4A a=-1.2 m/s
  8. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    v=u+at I have calculated part one as v=u+at 0+1.2(4) =4.8 m/s the part 2 deceleration I'm using same formula n v=u+at and as you say using constant velocity of 4 4+(1.2)(4)=8.8 m/s that's what I'm getting
  9. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    4+(1.2)(4)=8.8 m/s
  10. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    v=u+at 8+(1.2)(4)=12.8 m/s
  11. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    v=u+at 0+1.2(4) =4.8 m/s
  12. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    ok deceleration v = u +at
  13. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    units would be m/s
  14. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    v = u +at I have no deceleration formula
  15. alsy

    Maximum Velocity= 4.8 m/s2Deceleration= -1.2m/s2

    Homework Statement a lift accelerates from rest at 1.2m/s2 for 4 seconds..it travels at a constant velocity for 8 seconds and comes to rest in 3 seconds.calculate 1)the maximum velocity 2)deceleration in the final 3 secondsHomework Equations calculate 1)the maximum velocity 2)deceleration in...
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