Recent content by ambnj99

yes, I too have been looking into it, The above strain is wrong, as you stated with E value my book states shear strain to be: strain= ΔL= (1/G)(F/A) =(1/2.4×10^10 N/m^2)(25.5N/(1.77 x 10 ^-6 N/m^2) =2.10 x 10^-5 m so I am going with this for my solution for strain.

Is anyone certain of how to calculate the strain?

I wasn't sure what to due for calculating the strain, so i used the eq. tht included E... the question is word for word: The shear modulus of aluminum is 2.4 × 1010 N/m2. An aluminum nail of radius 7.5 × 10–4 m projects 0.035 m horizontally outward from a wall. A man hangs a wet raincoat of...

So I did some more digging, this is what i got, is it correct? E= 7.0 x 10^10 N/m^2 (youngs modulus of aluminum) A= 1.77 x 10 ^-6 N/m^2 vertical deflection: deltaY= (F/A)(L/G) (25N/(1.77 x 10 ^-6 N/m^2))/(0.035m/(2.4×10^10 N/m^2)) = 2.06 x10^-5 m stress= F/A = 25N/(1.77 x 10 ^-6...

The shear modulus of aluminum is 2.4 × 1010 N/m2. An aluminum nail of radius 7.5 × 10–4 m projects 0.035 m horizontally outward from a wall. A man hangs a wet raincoat of weight 25.5 N from the end of the nail. Assuming the wall holds its end of the nail, what is the vertical deflection of...