yes, I too have been looking into it,
The above strain is wrong, as you stated with E value my book states shear strain to be:
strain= ΔL= (1/G)(F/A)
=(1/2.4×10^10 N/m^2)(25.5N/(1.77 x 10 ^-6 N/m^2) =2.10 x 10^-5 m
so I am going with this for my solution for strain.
I wasn't sure what to due for calculating the strain, so i used the eq. tht included E...
the question is word for word:
The shear modulus of aluminum is 2.4 × 1010 N/m2. An aluminum nail of radius
7.5 × 10–4 m projects 0.035 m horizontally outward from a wall. A man hangs a wet raincoat of...
So I did some more digging, this is what i got, is it correct?
E= 7.0 x 10^10 N/m^2 (youngs modulus of aluminum)
A= 1.77 x 10 ^-6 N/m^2
vertical deflection: deltaY= (F/A)(L/G) (25N/(1.77 x 10 ^-6 N/m^2))/(0.035m/(2.4×10^10 N/m^2)) = 2.06 x10^-5 m
stress= F/A = 25N/(1.77 x 10 ^-6...
The shear modulus of aluminum is 2.4 × 1010 N/m2. An aluminum nail of radius
7.5 × 10–4 m projects 0.035 m horizontally outward from a wall. A man hangs a wet raincoat of weight 25.5 N from the end of the nail.
Assuming the wall holds its end of the nail, what is the vertical deflection of...