Recent content by amibhatta

[/tex] sinZ = C1*Z Z = (\alpha)*(\lambda) C1 =(+/-)[Sin(\alpha)] / (\alpha) hence we get, Sin((\alpha)*(\lambda)) = \lambda *sin(\alpha) \lambda = a+ib hence eqn1 and eqn2...

Hi, Thank for ur reply, Reply 1: I will look into it... thanx... Reply 2: 'h' means hyperbolic function... and the result u have showed is from where i started to get these equations... these are transcedental equations having many roots so that eqn formed at the end that you got is...

how to solve eqn1 = sin((alpha)*a)*cosh((alpha)*b)=sin(alpha)*a eqn2 = sinh((alpha)*b)*cos((alpha)*a) = b*sin(alpha) alpha = 0 to 2pi... Find a & b... Plz help me with any method that would help solving this...