Recent content by an9890

^ (a) ∑ Fx = ma --> mgsinΘ - fk = ma ∑ Fy = 0 --> n - mgcosΘ = 0 n = mgcosΘ and fk = mukn so muk = (gsinΘ -a) / gcos Θ

coefficient of kinetic friction, URGENT need today The system shown in the figure below has an acceleration of magnitude 0.51 m/s2, where m1 = 4.30 kg and m2 = 6.00 kg. Assume that the coefficient of kinetic friction between block and incline is the same for both inclines. Link to figure...