Recent content by anandtr2006

so overtaking distance is the length of the road which needs to be traveled by the faster car in order to overtake the slower car. distance on the road = velocity with respect to road x time of overtaking d = (17 m/s) x 2 = 34 m. so 34m should be the answer. right ?

I don't quite get your question. the faster car's real speed is 16.7 m/s. But since relative velocity is taken, the velocity of the car relative to the slower car is 5 m/s. Thus it can travel 10 metres in only two second ? Am I right ?

okk.. but there is nothing in the question about the safety distance ? is that information necessary to solve this question ? the distance between [the back of the overtaking car before ] and [the front of the overtaking car afterwards] is 15 m.

Homework Statement A car traveling at 60 kmph overtakes another car traveling at 42 kmph. Assuming each car to be 5.0 m long, find the time taken during the overtake and the total road distance used for the overtake.[/B]Homework Equations Relative Velocity of a body A with respect to another...

Fluid Mechanics by Cengel is certainly a very good book. As for exams are concerned, i think Fluid Mechanics b Rajput is better