Recent content by Anders Hijul
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Velocity due to known acceleration
That make sense Thank you!- Anders Hijul
- Post #13
- Forum: Introductory Physics Homework Help
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Velocity due to known acceleration
Thanks PeroK and PSN03 I think I got it! So the impulse is calculated from force applied, which is 75 N (area under the graph). So for 10 s we have J = F*t = 75 N*10 s = 75 N s So we have J = pf-pi 75 N = 10 kg*v -> v = 7,5 m/s So the final velocity after 10 s is 10 + 7,5 = 17,5 m/s It...- Anders Hijul
- Post #11
- Forum: Introductory Physics Homework Help
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Velocity due to known acceleration
I think I maybe haven't explained myself correctly I want to find the velocity of the object to t = 10 s When I have the force applied to the object over time, I can calculate the acceleration from F = ma, so I get a = 1 m/s^2 for t = 0 to t = 5 a = 0,8 m/s^2 for t = 6 a = 0,6 m/s^2 for t = 4...- Anders Hijul
- Post #7
- Forum: Introductory Physics Homework Help
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Velocity due to known acceleration
I meant that the graph would be 20-2t for t = 5 to 5 = 10 s But integrated the graph is 20t - t^2 But I think I am doing something wrong before this- Anders Hijul
- Post #5
- Forum: Introductory Physics Homework Help
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Velocity due to known acceleration
Sorry my mistake I meant t instead of x- Anders Hijul
- Post #3
- Forum: Introductory Physics Homework Help
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Where Can I Find Help with My Daily Homework?
Thank you :smile:- Anders Hijul
- Post #4
- Forum: New Member Introductions
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Velocity due to known acceleration
I have some troubles with this relatively simple problem My idea was to find the acceleration by F = ma and then integrate the graph and then find the velocity to t = 10 s + start velocity The graph will be - 2x And integrated -x¨^2 But this seems wrong Thanks in regards- Anders Hijul
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- Acceleration Velocity
- Replies: 13
- Forum: Introductory Physics Homework Help
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Where Can I Find Help with My Daily Homework?
Hope to get some help with my daily homework.But I cannot figure out, where to post questions.Thanks in regards.- Anders Hijul
- Thread
- Replies: 3
- Forum: New Member Introductions