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Tension in Cables of Differing Angles
Homework Statement α=30° β=45° m=10kg a=0 Tα=unknown Tβ=unknown THE ANSWERS SHOULD BE Ta=72N, Tβ=88N Homework Equations mg=10kg*9.8m/s2=98N ∑Fx=ma(x)=0 ∑Fy=ma(y)=0 A Free Body Diagram would show three forces: 98N facing downwards, Ta facing 30° up and to the left, and Tb...- Aninnymoose
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- Angles Cables Tension
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- Forum: Introductory Physics Homework Help